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The integral `intcos(log_(e)x)dx` is equal to: (where C is a constant of integration)A. `x[cos(log_(e)x)-sin(log_(e)x)]+C`B. `x/2[sin(log_(e)x)-cos(log_(e)x)]+C`C. `x[cos(log_(e)x)+sin(log_(e)x)]+C`D. `x/2[cos(log_(e)x)+sin(log_(e)x)]+C` |
Answer» Correct Answer - 4 | |