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The integrating factor of the differential equation ` (y log y) dx = (log y - x) dy ` isA. `1/(logy)`B. log(logy)C. `1+logy`D. logy

Answer» Correct Answer - d
Given differential eqution can be rewritten as
` (dx)/(dy) = ((log y -x))/((y log y)) rArr (dx)/(dy) + x/(y log y) = 1/y`
` :. IF = e^(int 1/(y log y)dy)=e^(log log y) = log y`


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