1.

The interionic distance for cesium chloride crystal will be

Answer»

a
a/2
`sqrt3 a//2`
`2a//sqrt3`

Solution :CSCL have SIMPLE cubic structure. In this structure body idagenal of simple cube `sqrt3 a = 2 XX (r_(CS^(+)) + r_(Cl^(-)))` So interionic distance `= 2 xx (r_(CS^(+)) + r_(Cl^(-)))`


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