The interionic distance for cesium chloride crystal will beA. aB. a/2C

1.	The interionic distance for cesium chloride crystal will beA. aB. a/2C. `sqrt3 a//2`D. `2a//sqrt3`
Answer» Correct Answer - C CsCl have simple cubic structure. In this structure body idagenal of simple cube `sqrt3 a = 2 xx (r_(CS^(+)) + r_(Cl^(-)))` So interionic distance `= 2 xx (r_(CS^(+)) + r_(Cl^(-)))`

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The interionic distance for cesium chloride crystal will beA. aB. a/2C. `sqrt3 a//2`D. `2a//sqrt3`

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