The internal energy changes in the conversion of 1.0 mole of the calcite from of CaCO_(3) to the aragonite from is +0.21 kJ . Calculate the enthalpy change when the pressure is 0.1 bar, given that the densities of the solids are 2.71 g cm^(-3) and 2.93 g cm^(-3) respectively.

The internal energy changes in the conversion of 1.0 mole of the calci

1.	The internal energy changes in the conversion of 1.0 mole of the calcite from of CaCO_(3) to the aragonite from is +0.21 kJ . Calculate the enthalpy change when the pressure is 0.1 bar, given that the densities of the solids are 2.71 g cm^(-3) and 2.93 g cm^(-3) respectively.
Answer» <P> Solution :`DELTAH = DeltaE + PDeltaV` Given `DeltaE = +0.21 kJ mol^(-1) = 0.21 XX 10^(3) J mol^(-1)` P = 1 bar = `1.0 xx 10^(5)` Pa `DeltaV = V_("argonite") - V_("calcite")` (mol. Wt. of `CaCO_(3)=100`) `=(100/2.93)- (100/2.71) CM^(3) mol^(-1)` of `CaCO_(3)` `=-2.77 cm^(3) = -2.77 xx 10^(-6) m^(3)` `DeltaH = 0.21 xx 10^(3) - 1 xx 10^(5) xx 2.77 xx 10^(-6)` `=2.0972 J mol^(-1)` `=0.20972 kJ mol^(-1)`