1.

The inversion of cane sugar proceeds with half- life of 500 minutes at pH=6 for any concentration of sugar. However, if pH=5, the half-life changes to 50 minutes. The rate law expression for the sugar inversion can be written as

Answer»

`r=k["sugar"]^(2)[H]^(6)`
`r=k["sugar"]^(1)[H^(+)]^(0)`
`r=k["sugar"]^(1)[H^(+)]^(1)`
`r=k["sugar"]^(0)[H^(+)]^(1)`

SOLUTION :`((t_(1//2))_(1))/((t_(1//2))_(2))=([H^(+)]_(2))/([H^(+)]_(1))`
`(500)/(50)={(10^(-5))/(10^(-6))}^(x)`
`1=x`


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