1.

The iodide is quantitatively converted to chloride when it is heated in a stream of chlorine. XI_(3) + 3Cl_(2) rarr XCl_(3) + I_(2) It 1 gm of XI_(3) is converted into (1)/(3) gm of XCl_(3) then atomic mass of X is :

Answer»

`30.75 gm`
`20.5 gm`
`61.5 gm`
`10.25 gm`

Solution :`{:(2XI_(3),+,3Cl_(2),rarr,2XCl_(3),+,3I_(2),),(1 gm,,,,(1)/(3) gm,,,):}`
Let atomic mass of X be M
`n_(XI_(3)) = n_(XCl_(3))`
`(1)/(M + 381) = ((1)/(3))/(M + 106.5)`
`M + 106.5 = (M)/(3) + 127`
`(2M)/(3) = 20.5`
`M = 30.75 gm`


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