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The iodine molecule dissociates into atoms after absorbing light of 4500Å. If one quantum of radiat is absorbed by each molecule, calculate the kinetic energy of iodine atoms (Bond energy I_(2) = 240 kJ mol^(-1)) |
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Answer» Solution :Bond energy PER molecule of `I_(2) = (240 xx 1000J)/(6.022 xx 10^(23)) = 3.985 xx 10^(-19)J` Energy absorbed `= (HC)/(lamda) = ((6.626 xx 10^(-34) Js) (3 xx 10^(8) ms^(-1)))/(4500 xx 10^(-10)m) = 4.417 xx 10^(-19)J` The difference of energy absorbed and energy used for dissociation of bond in `I_(2)` gives the KINETIC energy one `I_(2)` molecule. `:.` K.E. of one `I_(2)` molecule `= (4.417 xx 10^(-19) - 3.985 xx 10^(-19)) J = 4.32 xx 10^(-20)J` `:.` K.E. of one iodine atom `= (4.32 xx 10^(-20))/(2) J= 2.16 xx 10^(-20)J` |
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