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The ion that cannot be precipitate by both HCI and H_(2)S is |
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Answer» `Pb^(2+)` `2Cu^(o+) hArr Cu^(2+) +Cu` `K = ([Cu^(2+)])/([Cu^(o+)]^(2)) = 1.6 xx 10^(6)` THUS , the concentration of `Cu^(o+)` ion is verysmall , and HENCE it cannotbeprecipitate |
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