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The ion that cannot be precipitated by both HCl and H_(2)S is |
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Answer» `PB^(2+)` `2Cu^(+)hArrCu^(2+)+Cu` `K=([Cu^(2+)])/([Cu^(+)]^(2))=1.6xx10^(6)` THUS, the concentration of `Cu^(+)` ion is very small and hence it cannot be precipitated. |
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