1.

The ionic conductance of Ba^(2+) and CI^(-)are respectively127 and 76 omega^(-1)cm^(2)of BaCI_(2)at infinitedilution will be

Answer»

139.5
203
279
101.5

Solution :The equivelnt weight of `BaCI_(2)=("Molecular weight")/(2)`
`lambda_(m)^(INFTY) "for" BaCI_(2) = lambda_(m)^(infty) Ba^(2+) +2 lambda_(m)^(infty) CI^(-)`
`therefore lambda_(eq)^(infty) for BaCI_(2) =1//2 lambda_(m)^(infty) Ba^(2+) + lambda_(m)^(infty) CI^(-)`
`=127//2+76 =139.5 "ohm"^(-01) cm^(-2)`


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