1.

The ionic equivalent conductivities of `C_(2)O_(4)^(2-),K^(o+),` and `Na^(o+)` ions are `x,y,` and `z S cm^(2) Eq^(-1)` respectively. Calculate `wedge_(eq)^(@)` of `(NaOOC-COOK).`

Answer» Total charge`=2`
Number of equivalent of ion `=("Charge on the ions")/("Total charge")`
`:. ` Equivalent of `C_(2)O_(4)^(2-)=(2)/(2)=1`
Equivalent of `Na^(o+)=(1)/(2), Eq of K^(o+)=(1)/(2)`
`:. wedge _(eq(NaOOC-COOK))^(@)=lambda_(eq(C_(2)O_(4)^(2-)))^(@)+(1)/(2)lambda_(eq(Na^(o+)))^(@)+(1)/(2)lambda_(eq(K^(o+)))^(@)`
`=(x+(y)/(2)+(z)/(2))`


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