1.

The ionic radii (Å)" of "C^(4+) and O^(2-)respectively are 2.60 and 1.40. The ionic radius of the isoelectronic ion N^(3-) would be

Answer»

2.6
1.71
1.4
0.95

Solution :The ionic radii of isoelectronic IONS DECREASE with the increase in the MAGNITUDE of the nuclear CHARGE.
So, decreasing order of ionic radii is `C^(4-)gtN^(3-)gtO^(2-)`.


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