1.

The ionic radii of A^(+) and B^(-) are 0.98xx10^(-10)m and 1.81xx10^(-10)m, the coordination number of each ion in AB is ………… .

Answer»

8
2
6
4

Solution :Hint : `(r_(c.))/(r_(A^(-)))=(0.98xx10^(-10))/(1.81xx10^(-10))=0.54`
It is in the RANGE of 0.414 0.732, HENCE the coordination number of each ion is 6.


Discussion

No Comment Found

Related InterviewSolutions