The ionic radii of A^+ and B^- ions are 0.92xx10^(-10) m and 1.81xx10^(-10) m . The coordination number of each ion in AB is

The ionic radii of A^+ and B^- ions are 0.92xx10^(-10) m and 1.81xx10^

1.	The ionic radii of A^+ and B^- ions are 0.92xx10^(-10) m and 1.81xx10^(-10) m . The coordination number of each ion in AB is
Answer» 2 6 4 8 Solution :Radius ratio , `r_(+)/r_(-)=(0.98xx10^(-10))/(1.81xx10^(-10))=0.541` It lies in the RANGE 0.414-0.732 . HENCE, coordination NUMBER of each ION will be 6, as in the CASE of NaCl