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The ionic radii of `A^(+) and B^(-)` ions are ` 0.98 xx 10^(-10) m and 1.81 xx 10^(-10) m`. The coordination number of each ion in AB isA. 2B. 6C. 4D. 8

Answer» Correct Answer - A
Radius ratio , ` r_(+)/r_(-) = ( 0.98 xx 10^(-10))/( 1.81 xx 10^(-10)) = 0.541`
It liess in the range 0.414 - 0.732. Hence, coordination number of each ion will be 6, as in the case of NaCl.


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