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The ionic radii of `A^(+) and B^(-)` ions are `0.98 xx 10^(-10) and 1.81 xx 10^(-10) m` .The coordinatyion number of each ion in `AB` isA. `2`B. `6`C. `4`D. `8` |
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Answer» Correct Answer - b `(r_(A+))/(r_(B+)) = (0.98 xx 10^(-10))/( 1.81 xx 10^(-10)) = 0.54` `as (r^(+))/(r^(-)) `is in rabge `414 - 732` so octabedral Co-ordination no of each in `6` like `NaCI` structure |
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