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The ionic radii of `A^(+)` and `B^(-)` ions are `0.98xx10^(-10)m` and `1.81xx10^(-10)m`.The coordination number of each ion in `AB` is :A. `2`B. `6`C. `4`D. `8` |
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Answer» Correct Answer - 2 Let calculate the radius ratio: `(r_(+))/(r_(-))=(0.98xx10^(10)m)/(1.81xx10^(-10)m)=0.541` Since it lies the range `0.414-.732` ,the coordination number of each ion is `6`. |
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