The ionic radii of A^(+) and B^(-) ions are0.98 xx 10^(-10) m and 1.81 xx 10^(-10) m.The coordination number of each ion in AB is

The ionic radii of A^(+) and B^(-) ions are0.98 xx 10^(-10) m and 1.81

1.	The ionic radii of A^(+) and B^(-) ions are0.98 xx 10^(-10) m and 1.81 xx 10^(-10) m.The coordination number of each ion in AB is
Answer» 2 6 4 8 Solution :Radius RATIO , ` r_(+)/r_(-) = ( 0.98 xx 10^(-10))/( 1.81 xx 10^(-10)) = 0.541` It liess in the range 0.414 - 0.732. Hence, coordination NUMBER of each ION will be 6, as in the case of NaCl.