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The ionic radii of `Rb^(+)` and `I^(-)` are 1.46 and `2.16Å`. The most probable type of structure exhibited by it is:A. CsCl typeB. ZnS typeC. NaCl typeD. `CaF_2` type |
Answer» Correct Answer - C According to radius ratio rule, `(r_(c^+)(Rb^+))/(r_(a)(I^-)) = (1.46)/(2.16) = 0.676` It will have coordination number 6 and structure will be same as of NaCl |
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