1.

The ionisation energy of gaseous Na atoms is 495.8 KJ mol^(-1). The lowest possible frequency of light that can ionise a Na atom is

Answer»

`1.24xx10^(15) s^(-1)`
`4.76 XX 10^(14) s^(-1)`
`1.24xx10^(12) s^(-1)`
`3.15 xx 10^(14) s^(-1)`

Solution :E=hv or v=`E/h`
`=(495.8xx10^(3) "J/atom")/(6.02xx10^(23))xx(1)/(6.62xx10^(-34)JS)`
`=1.24xx10^(14)s^(-1)`


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