1.

The ionisation energy of H atom is x kJ. The energy required for the electron to jump from n=2 to n=3 will be

Answer»

5X
36x/f
5x/36
9x/4

Solution :I.E. `=E_(OO)-E_(1)`
`=0-(-1311.8/1)=1311.8=x`
Energy required `=-1311.8/(3^(2))-(-1311.8/(2^(2)))`
`-x/9+x/4` or `(5x)/36`.


Discussion

No Comment Found