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The ionisation energy of hydrogen is 13.6 eV . The energy of the photon released when an electron jumps from the first excited state (n=2) to the ground state of hydrogen atom isA. 3.4 eVB. 4.53 eVC. 10.2 eVD. 13.6eV |
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Answer» Correct Answer - C The energy rquired to removed electron in the first excited state (n=2) The energy of the photon `Rhc((1)/(1^(2))-(1)/(n^(2)))` `rArr" " 13.6((1)/(4)-(1)/(4))=13.6((4-1)/(4))` `" " =13.6 xx(3)/(4)=(40.8)/(4)=10.2eV` |
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