1.

The ionisation potential of Hydrogen is 2.17 xx 10^(-11) erg/atom. The energy of the electron in the second orbit of the hydrogen atom is

Answer»

`-(2.17 xx 10^(-11))/(2) ` erg/atom
`-(2.17 xx 10^(-11))/(2^2) ` erg/atom
`-(2.17 xx 10^(-17))/(2^2) ` erg/atom
`-(2.17 xx 10^(11))/(2^2) ` erg/atom

SOLUTION :`E = - IE =(2.18 xx 10^(-11))/((2)^2) ` erg/atom


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