The ionization constant `(K_(a))` of a weak electrolyte is `2.5xx10^(-7)`, while `wedge_(eq)` of its `0.01M` solution is `19.65S cm^(2) eq^(-1)wedge^(@)._(eq)` is `……………….` .

The ionization constant `(K_(a))` of a weak electrolyte is `2.5xx10^(-

1.	The ionization constant `(K_(a))` of a weak electrolyte is `2.5xx10^(-7)`, while `wedge_(eq)` of its `0.01M` solution is `19.65S cm^(2) eq^(-1)wedge^(@)._(eq)` is `……………….` .
Answer» Correct Answer - `(392 S cm^(2) eq^(-1))` `(392 S cm^(2) eq^(-1))` `K_(a) = c alpha^(2)` `2.5xx 10^(-7)=10^(-2)xxalpha^(2)impliesalpha=5xx10^(-2)` `alpha=(wedge^(c)._(eq))/(wedge^(@)._(eq))` `=5xx10^(-2)=(19.65)/(wedge^(@)._(eq))implieswedge_(eq)^(@)=392 S cm^(2)eq^(-1)`

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The ionization constant `(K_(a))` of a weak electrolyte is `2.5xx10^(-7)`, while `wedge_(eq)` of its `0.01M` solution is `19.65S cm^(2) eq^(-1)wedge^(@)._(eq)` is `……………….` .

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