1.

The ionization constant of ammonium hydroxide is 1.77 xx 10^(-5) at 298 K. Hydrolysis constant of ammonium chloride is :

Answer»

`6.5xx10^(-12)`
`5.65xx10^(-13)`
`5.65xx10^(-12)`
`5.65xx10^(-10)`

Solution :Ammonium chloride is a SALT of weak BASE and strong ACID. In this case, hydrolysis constant `K_h` can be calculated as
`K_h=K_w/K_b=(1.0xx10^(-14))/(1.77xx10^(-5))`
`=5.65xx10^(-10)`


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