The ionization constant of aniline and acetic acid and water at 25^(0)C are respectively 3.83 xx 10^(-10), 1.75 xx 10^(-5) and 1 xx 10^(-14). Calculate the percentage hydrolysis of aniline acetate in a decinormal solution

The ionization constant of aniline and acetic acid and water at 25^(0)

1.	The ionization constant of aniline and acetic acid and water at 25^(0)C are respectively 3.83 xx 10^(-10), 1.75 xx 10^(-5) and 1 xx 10^(-14). Calculate the percentage hydrolysis of aniline acetate in a decinormal solution
Answer» `54.95` `9.54` `4.6` `42.3454` Solution :Aniline acetate issalt of weak acid and weak base, its degree of hydrolysis may be calculated USING following formula `alpha = sqrt((K_(H))) = sqrt(((K_(W))/(K_(a) xx K_(b))))"......"(i)` Where `K_(q) = 10^(-14)` `K_(a) = 1.75 xx 10^(-5), K_(b) = 3.83 xx 10^(-10)` `alpha = sqrt(((10^(-14))/(1.75 xx 10^(-5) xx 3.83 xx 10^(-10)))) = 1.22` Which is not possible because, degree of of hydrolysis may be notbe greater than `1`. Thus, we have no avoid the APPROXIMATION. `(alpha)/(1-alpha) = sqrt((K_(h))) = 1.22 , alpha = (1.22)/(2.22) = 0.5495` `%` hydrolysis `= alpha ' 100` `= 0.5495 xx 100 = 54.95%`