InterviewSolution
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InterviewSolution
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The ionization energies of Li and Na are `520 kJ mol ^-1 and 495 kJ mol ^-1` respectively. The energy required to convert all the atoms present in 7 mg of Li vapours and 23 mg of sodium vapours to their respective gaseous captions respectively are :A. 52 J,49.5 JB. 520 J,495 JC. 49.5 J,52 JD. 495 J,520 J |
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Answer» Correct Answer - B No. of moles of Li=`(7)/(1000X7)=10^(-3)` No. of moles of NA=`(23)/(1000xx23)=10^(-3)` `therefore` The amount of energies required for `10^(-3)` mole each of Li and Na are 520 `KJX10^(-3) and 495 KJ X10^(-3)` or 520 J and 495 J respectibely. |
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