The ionization energy of H-atom is 13.6 ov. The ionization energy of L – InterviewSolution

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1.

The ionization energy of H-atom is 13.6 ov. The ionization energy of L2 ion wil be(1)54.4 e(2) 122.4 ov(3) 13.6 eV(4) 272 eV

Answer»

E = (-13.6xZ2) / n2eV

where, n = number of orbit = 1

Z = atomic number = 2 (for He)

E = (-13.6x22) / 12

E = (-13.6x4) = -54.4 eV

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