1.

The ionization energy of hydrogen in excited state is `+0.85 eV`. What will be the energy of the photon emitted when it returns to the ground state?

Answer» Energy of H-atom in the ground state `= - 13.6 eV`
Ionization energy of hydrogen in excited state equal to `+0.85 eV` means
Energy of H-atom in the excited state `= - 0.85 eV`
`:.` Energy emitted `= -0.85 eV - (-1.6 eV) = 12.75 eV`


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