1.

The ionization energy of lithium is 520 kJ "mol"^(-1) . Find the amount of energy (in kJ) required to convert 70 mg of lithium atoms in gaseous state into Li+ ions.

Answer»


Solution :70 MG `=70 XX 10^(-7) G = (70 xx 10^(-3))/7 mol = 1 xx 10^(-2)` mol
`therefore` Amount of energy required
`= 1 xx 10^(-2) xx 520 kJ = 5.2 kJ`


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