The ionizationenergyof hydrogenatomis 1.312 xx 10^(6) J mol^(-1)calculatethe energyrequirefor jumpof electron from n=1 ton=2

The ionizationenergyof hydrogenatomis 1.312 xx 10^(6) J mol^(-1)calcul

1.	The ionizationenergyof hydrogenatomis 1.312 xx 10^(6) J mol^(-1)calculatethe energyrequirefor jumpof electron from n=1 ton=2
Answer» `9.56 xx 10^(5) j//mol` `7.56 xx 10^(5) j//mol` `9.84 xx 10^(5) j//mol` `8.51 xx 1 0^(5) j//mol` Solution :`Delta E= 1.312 xx 10^(5) ((1)/(n_(1)^(2)) -(1)/(n_(2)^(2))) mol^(-1)` `=1.312 xx 10^(6)((1)/(1)-(1)/(4))` `=9.84 xx 10^(5)J mol^(-1)`