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The joint equation of bisectors of angles between lines `x=5` and `y=3` isA. `(x-5)(y-3)=0`B. `x^2-y^(2)-10x+6y+16=0`C. `x^2-y^(2)-10x+6y+16=0`D. `xy=0` |
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Answer» Correct Answer - B The equation of the bisector of the angle between the lines `(x-5) and (y-3)` is `(((x-5))/(sqrtt^(2)))= pm ((y-3)/(sqrtt^(2))) Rightarrow (x-5)/(1)= pm (y-3)/(1)` `Rightarrow x-5=+ (y-3) and x-5=-(y-3)` `Rightarrow (x-y-2)=0 and (x+y-8)=0` `therefore ` Combined equation of bisector of angle between the lines is `(x-y-2)(x+y-8)=0` `Rightarrow x^(2)+xy-8x-xy-y^(2)+8y-2x-2y-16=0` `Rightarrow x^(2)-y^(2)-10x+6y+16=0` |
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