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The `K_(alpha)` X-ray emission line of lungsten accurs at `lambda = 0.021 nm`. What is the energy difference between `K`and `L` levels in the atom?A. `0.51 MeV`B. `1.2 MeV`C. `59 keV`D. `13.6 eV`

Answer» Correct Answer - C
`DeltaE=1242/(lambda(nm))eV=1242/0.021=59142 eV~= 59KeV`


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