1.

The K.E of N molecules of O_(2)is x Joules at -123°C. Another sample of O_(2) at 27°C has a KE of 2x Joules. The latter sample contains________N molecules of O_(2).

Answer»

SOLUTION :`(K.E_1)/(K.E_2) = (n_1T_1)/(n_2T_2)` .


Discussion

No Comment Found