1.

The K, of an indicator HIn is 9 x 10^(4), The percentage of the basic form of indicator is 10x in a solution of pH = 4. What is x ?

Answer»


SOLUTION :` PH =pK_(In)+LOG"" (In^(-))/( HI_n) , 4 =4- log 9 +log ""(In^(-))/(HI_n)`
` 9= ( In^(-))/( HI_n) RARR % " of " In^(-)=90 %`


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