1.

The K_(p) " value for reaction " H_(2) + I_(2) hArr 2 HI " at "460^(@)C " is 49. If intial pressure of " H_(2) and I_(2)" is "0*5 atm respectively , determine the partial pressure of each gas at equilibrium.

Answer»

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Solution :`{:(,H_(2),+,I_(2),hArr,2 HI),("Intial ",0*5,,0*5,,0),("At. EQM.",0*5-x,,0*5-x,,2" "x):}`
`K_(p) = (2x)^(2)/(0*5-x)^(2) = 49 or (2 x)/(0*5 - x)=7 or 2 x = 3*5- 7 x`
or ` 9 x = 3*5 or x= (3*5)/9=0*39`
`:. " Pressure of " H_(2) and I_(2) " at eqm."= 0*5 - 0*39= 0*11 " atm"`
Pressure of HI at eqm. `= 2 xx 0*39 = 0*78 " atm "`


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