InterviewSolution
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InterviewSolution
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The `K_(sp)` of `Mg(OH)_(2)` is `1xx10^(-12). 0.01M Mg^(2+)` will precipitate at the limiting pH ofA. `8`B. `9`C. `10`D. `12` |
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Answer» Correct Answer - B `{:(Mg(OH)_(2)rarr,Mg^(2+)+,2overset(Theta)OH,),(,S,2S,):}` Let `S_(1)` is the solubility in `0.1M MgCI_(2)` (common ion `Mg^(2+))` `:. [Mg^(2+)] = (S_(1) + 0.001) ~~ 0.01` `[overset(Theta)OH] = 2S_(1)` `K_(sp) = (0.01) (2S_(1))^(2)` `S_(1) = ((K_(sp))/(4xx0.01))^(1//2) = ((10^(-12))/(4xx10^(-2)))^(1//2) = 0.5xx10^(-5)M` `:. [overset(Theta)OH] = 2S_(1) = 2xx 0.5 xx 10^(-5) = 10^(-5)M` `pOH = 5, pH = 14 - 5 = 9` |
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