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The K_(sp) of PbSO_4 is 1.44xx10^(-8) then calculate concentration of Pb^(2+). |
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Answer» Solution :`S=sqrtK_(sp)` `=SQRT(1.44xx10^(-8))=sqrt(144xx10^(-6))=12XX10^(-3)` `=1.2xx10^(-2) M`=0.012 M =`[Pb^(2+)]` |
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