1.

The kα X-ray of molybdenum has wavelength 0.071 nm. If the energy of a molybdenum atoms with a k electron knocked out is 27.5 keV, the energy of this atom when an L electron is knocked out will be (in keV). (Round off to the nearest integer)[h=4.14×10−15 eVs, c=3×108 ms−1]

Answer» The kα X-ray of molybdenum has wavelength 0.071 nm. If the energy of a molybdenum atoms with a k electron knocked out is 27.5 keV, the energy of this atom when an L electron is knocked out will be

(in keV). (Round off to the nearest integer)

[h=4.14×1015 eVs, c=3×108 ms1]


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