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The kinetic energy of `4 mol` of nitrogen gas at `127^(@) C` is …….. `cal(R = 2 cal mol^(-1) K^(-1))`A. `4400`B. `3200`C. `4800`D. `1524` |
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Answer» Correct Answer - C According to the kinetic molecular theory , kinetic energy `(KE)` for `n` moles is given as `KE = (3)/(2) nRT` `= (3)/(2) (4 "mol") (2 "cal mol"^(-1) K^(-1)) (400 K)` `= 4800 cal` |
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