The kinetic energy of a body is increased by 100%. what is the change

1.	The kinetic energy of a body is increased by 100%. what is the change in momentum of the body?
Answer» We have, Kinetic energy, K = 1/2 mv^2 Where 'm' is the mass of the OBJECT and 'v' is the VELOCITY of linear motion. Similarly, Linear MOMENTUM, P = mv On solving the 2 equations, we get the direct RELATION between P and K. K = P^2/2m Or k is proportional to P^2 It is said that linear Kinetic energy raised by 100%, so new Kinetic energy, K= 2 K To find the new momentum P, K∗/K=(P∗/P)2K∗/K=(P∗/P)2 2K/K=(P∗/P)22K/K=(P∗/P)2 2=(P∗/P)22=(P∗/P)2 P∗=√2PP∗=√2P The momentum increases √2 times.

The kinetic energy of a body is increased by 100%. what is the change in momentum of the body?

Answer»

We have,
Kinetic energy,

K = 1/2 mv^2

Where 'm' is the mass of the OBJECT and 'v' is the VELOCITY of linear motion.

Similarly,
Linear MOMENTUM,

P = mv

On solving the 2 equations, we get the direct RELATION between P and K.

K = P^2/2m

Or k is proportional to P^2

It is said that linear Kinetic energy raised by 100%, so new Kinetic energy,
K*= 2 K

To find the new momentum P*,

K∗/K=(P∗/P)2K∗/K=(P∗/P)2

2K/K=(P∗/P)22K/K=(P∗/P)2

2=(P∗/P)22=(P∗/P)2

P∗=√2PP∗=√2P

The momentum increases √2 times.

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