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The kinetic energy of a lamina moving in its planeisA. `M(v_(cm)^(2) + K^(2)omega^(2))`B. `1/2M(v_(CM)^(2) + K^(2)omega^(2))`C. `1/2komegap^(2)`D. None of these |
Answer» b) if a lamina is moving with `v_(CM)` having angualr velocity `omega`. Then, KE = Angular kinetic energy + Translatory kinetic energy `=1/2_(CM)omega^(2) + 1/2 mv_(CM)^(2)` `=1/2MK^(2)omega^(2) + 1/2 Mv_(CM)^(2) = `1/2 M(K^(2)omega^(2)+ v_(CM)^(2))` |
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