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The kinetic energy of a sub-atomic particles is 5.85 xx 10^(-25)J. Calculate the frequency of the particle wave. (Planck's constant, h = 6.626 xx 10^(-34) kg m^(2) s^(-1)) |
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Answer» SOLUTION :K.E. `= (1)/(2) mv^(2) = 5.85 xx 10^(-25) J` By de Broglie equation, `lamda = (h)/(mv)` But `lamda = (u)/(V) :. (u)/(v) = (h)/(mv) or v (mv^(2))/(h) = (2 xx 5.85 xx 10^(-25)J)/(6.626 xx 10^(-34) Js) = 1.77 xx 10^(9) s^(-1)` |
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