Saved Bookmarks
| 1. |
The kinetic energy of the electron in an orbit of radius `r` in hydrogen atom is (`e =` electronic charge)A. `(e^(2))/(r )`B. `(e^(2))/(2r)`C. `(e^(2))/(r^(2))`D. `(e^(2))/(2r^(2))` |
|
Answer» Correct Answer - b `(mv_(n)^(2))/(r_(n))=(1)/(4pi epsilon_(0)).((ze^(2))/(r_(n)^(2)))=(kze^(2))/(r_(n)^(2))` `mv^(2) x=(Ze^(2))/(r_(v))` Kinetic energy of electron in `nth` orbit `KE=(1)/(2)mv_(n)^(2)=(kZe^(2))/(2r_(n))` or `KE=(e^(2))/(2r)` |
|