1.

The kinetic study of a reaction like vA rarr P at 300 K provides the following curve, where concentration is taken in mol dm^(-3) and time in min.

Answer»

N = 0, k = 4.0 mol `dm^(-3) min^(-1)`
`n=(1//2), k = 2.0 mol^(1/2) dm^(-3//2) min^(-1)`
n= 1, k= 8.0 `min^(-1)`
n - 2, k = 16.0 `dm^3 mol^(-1) min(-1)`

Solution : From the graph, `sqrt(r_0)=4[A]_0` …(i)
RATE = `k[A]_0^n` …(ii)
`therefore r_0 = 16[A]_0^2`
On comparing EQ. (ii) and (iii),we get,
k=`16dm^3mol^(-1)min^(-1)`,n = 2


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