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The larger of the two supplementary angles exceeds the smaller by 18°. Find them. |
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Answer» We know that two angles are supplementary angles if their sum is 180°. Let smaller angle is x°. Given that difference between supplementary angles are 18° Therefore, the other angle is x° + 18°. Hence, x° & x° + 18° are supplementary angles. Therefore, x° + x° + 18° = 180°. (By definition of supplementary angles) ⇒ 2 x° + 18° = 180°⇒ 2x° = 180° – 18° = 162° ⇒ x° = \(\frac{162°}{2}\) = 81°. And x° + 18° = 81°+18° = 99°. Hence, the angles are 81°, 99° |
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