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The largest and the shortest distance of the earth from the sun are r_1 and r_2respectively. Calculate the distance from the sun when it is at perpendicular distance to major axis of the orbit drawn from the sun |
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Answer» Solution :Since `E = c/a RARR c =ea "" THEREFORE r_1 = a+c=a+ea=a(1+e)` ` r_2 = a -c =a -ea = a (1-e)` Required distance`L = (b^2)/(a)` (semi latus rectum ) we have `r_1+r_2 = 2a` and `r_-r_2 =a(1+e) -a(1-e) = 2ae rArr e= (r_1-r_2)/(r_1+r_2)` Also `b^2 = a^2 (1-e^2)` ` therefore L = (b^2)/(a) = (a^2 (1-e^2))/(a) = a (1-e^2)` ` = ((r_1+r_2)/(2)) [1-((r_1-r_2)/(r_1+r_2))^2]` on simplification , `L = (2r_1r_2)/(r_1+r_2) "or " 2/L = (1)/(r_1) + (1)/(r_2)` |
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