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The largest oxidation number exhibited by an element depends on its outer electronic configuration. With which of the following outer electronic configurations the element will exhibit largest oxidation number? |
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Answer» `3d^(1)4s^(2)` = `(n-1)d" "e^(-)+NS" "e^(-)` SO, (A) `3d^(1)4s^(2)=1+2=3` (B) `3d^(3)4s^(2)=3+2=5` ( C) `3d^(5)4s^(1)=5+1=6` (D) `3d^(5)4s^(2)=5+2=7` |
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