The latent heat of fusion of ice is 336J/gm.Calculate the molar entropy of fusion of ice at normal melting point.

The latent heat of fusion of ice is 336J/gm.Calculate the molar entrop

1.	The latent heat of fusion of ice is 336J/gm.Calculate the molar entropy of fusion of ice at normal melting point.
Answer» to find the molar entropy of fusion of ice at normal MELTING POINT. if latent heat of fusion of ice is 336 J/g solution : latent heat of fusion of ice = 336 J/g molar mass of ice = 18g/mol [ ice is just water in solid form and we know, molar mass of water is 18g/mol so molar mass of ice = 18 g/mol ] now, molar latent heat of fusion of ice = 336 × 18 J/mol = 6048 J/mol normal melting point of ice, T = 0°C = 273 K now molar entropy of fusion of ice = molar latent heat of fusion of ice/normal melting point of ice = (6048 J/mol)/273 K= 22.154 J/mol/K THEREFORE the molar entropy of fusion of ice at normal melting point is 22.154 J/mol/K.also read similar questions : why latent heat of fusion of ice is less than latent heat of vaporisation of ice ? brainly.in/question/14344707Latent heart of fusion of ice is 0.333kJ/g. The increase in entropy when 1mole water MELTS at 0°C will be? brainly.in/question/1936200